Asked by Gian

A ship sails 15.0 mi on a course S40°10’W and then 21.0 mi on a course N28°20’W. Find the distance and direction of the last position from the first.
Answered by Steve
convert to (x,y) values and add:
15@S40°10'W = (-9.675,-11.463)
21@N28°20'W = (-9.967,18.484)
sum = (-19.642,7.021)
or,
[email protected]°W
Answered by Anonymous
xdgxcg
Answered by Anonymous
how did you get the [email protected]°W?
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