Asked by precious
A bullet of mass 3.0g moving at 500m/s hits a tree and pierced 20cm into the trunk of the tree.what is the resistimg force offered by the tree?
Answers
Answered by
drwls
Force * distance = Work done by bullet = Initial kinetic energy of the bullet
Solve for the force
F = M*V^2/(2*X)
= 3*10^-3*(500)^2/(2*0.2) Newtons
= 1875 N
Solve for the force
F = M*V^2/(2*X)
= 3*10^-3*(500)^2/(2*0.2) Newtons
= 1875 N
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