Question

A golf ball was hit and projected in an angle of 60 degrees with the horizontal. if the initial velocity of the ball was 50m/s, calculate the following:
a. the time the golf ball was in the air
b. horizontal distance the ball traveled
c. maximum height the ball reached

Answer 1

a) 2 Vo sin60/ g

b) 2 Vo^2 sin60 cos60/g = Vo^2 sin120/ g

c) Vo^2*sin^2 60/(2g)

Answer 2

8.83 s
221 m
95.66 m

Answer 3

Can i see the formula?

Answer 4

May i have your formula please!