Asked by YellowCorn
A golf ball was hit and projected in an angle of 60 degrees with the horizontal. if the initial velocity of the ball was 50m/s, calculate the following:
a. the time the golf ball was in the air
b. horizontal distance the ball traveled
c. maximum height the ball reached
a. the time the golf ball was in the air
b. horizontal distance the ball traveled
c. maximum height the ball reached
Answers
Answered by
drwls
a) 2 Vo sin60/ g
b) 2 Vo^2 sin60 cos60/g = Vo^2 sin120/ g
c) Vo^2*sin^2 60/(2g)
b) 2 Vo^2 sin60 cos60/g = Vo^2 sin120/ g
c) Vo^2*sin^2 60/(2g)
Answered by
Anonymous
8.83 s
221 m
95.66 m
221 m
95.66 m
Answered by
Draniele
Can i see the formula?
Answered by
BOHLEN LINAZA BALMORI
May i have your formula please!
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