Ask a New Question
Search
Question
A 1000 kg sports car is initially traveling at 30 m/s. A frictional force f, defined as a function of velocity v, f=-200v, acts on it. What would the frictional force on the car be at 5 seconds?
Answers
Answers
Related Questions
Related
147.5/1000= 0.1475 86.5/1000= 0.0865 Therefore 0.1475 x 0.0865 =0.0128m^2
1000 lockers 1000 students, the first student goes along and opens every other locker. The second st...
An initial investment of $1000.00 is appreciated for 5 years at 15% interest compounded semiannually...
A 0.90 × 10^3 kg sports car collides into the rear end of a 2.4 × 10^3 kg SUV stopped at a red light...
1000 yds of fence x 1000-x 1. Show that the area function to be maximized is A(x) = ( pi + 4...
a 1000 kg sports car accelerates from 0-30 m/s in 5.0 s. What is tge average power delivered by the...
Solve the initial initial value problem d^2x/dt^2+2DX/dt-3x =0, x(2π) = 0, x(2π) = 13
Think about the sports in the article. How are they alike and different? What is one way they are...
Convert 54/1000 54 1000 to a decimal.(1 point) Responses 0.054 0.054 0.54 0.54 5.4...
An initial investment of $1000 grows at an interest rate of 4% per year. How long will it take that...