Asked by LP
A Quadratic Word Problem
If one side of a square is increased by 2 inches and an adjacent side is decreased by 2 inches, the area of the resulting rectangle is 32 square inches. Find the length of one side of the square.
If one side of a square is increased by 2 inches and an adjacent side is decreased by 2 inches, the area of the resulting rectangle is 32 square inches. Find the length of one side of the square.
Answers
Answered by
Bosnian
a = length of one side of the square
W = Rectangle width
H = Rectangle height
A = Rectangle area
W = a + 2
H = a - 2
A = W * H
A = ( a + 2 ) * ( a - 2 ) = 32
32 = a ^ 2 + 2 a - 2 a - 4
32 = a ^ - 4 Add 4 to both sides
32 + 4 = a ^ - 4 + 4
36 = a ^ 2
a = sqrt ( 36 ) = 6
The length of one side of the square = 6 in
W = Rectangle width
H = Rectangle height
A = Rectangle area
W = a + 2
H = a - 2
A = W * H
A = ( a + 2 ) * ( a - 2 ) = 32
32 = a ^ 2 + 2 a - 2 a - 4
32 = a ^ - 4 Add 4 to both sides
32 + 4 = a ^ - 4 + 4
36 = a ^ 2
a = sqrt ( 36 ) = 6
The length of one side of the square = 6 in
Answered by
Ayah
6 inch
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