Asked by Marika

A baseball diamond is a square with sides 27.4m. The pitchers mound is 18.4m from home plate on the line joining home plate and second base. How far is the pitcher's mound from first base?

Answers

Answered by Kaj
At 19.39 meters

18.4^2+27.4^2-2*18.4*27.4Cos 45
D^2= 1089.32-812.99
D Sq root of 376.33
D= 19.39
Answered by Bhatti
How we got that the angle is 45
Answered by Nooo
It’s a square so each angle would be 90 degrees divide that by 2 since there would be a diagonal line and 90 divided by 2 is 45
Answered by JAMEL SUFIAN
your answer is right but the work is wrong - 812.99 should be 712.99
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