Asked by cal

Just one more.. Thanks for the last one!

16^(d-4) = 3^(3-d)

solve for d
Answered by Reiny
log both sides

log 16^(d-4) = log 3^(3-d)
(d-4)log16 = (3-d)log3
expand it
dlog16 - 4log16 = 3log3 - dlog3
dlog16 + dlog3 = 3log3 + 4log16
d(log16 + log3) = 3log3 + 4log16
d = (3log3 + 4log16)/(log16 + log3)
the rest is button pushing
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