bricks are stacked in 20 rows such that each row has a fixed number of bricks more than the row above it. the top row has 5 bricks and the bottom row 62 bricks. how many bricks are in the stack?

Answer 1

using your arithmetic sequence definitions

t1 = a = 5
t20 = a+19d = 62

5+19d = 62
19d = 57
d = 3

sum(20) = (20/2)(first + last)
= 10(5+62) = 670

Answer 2

how did you gt 19d ?

Answer 3

The formula for
term(n) = a + (n-1)d
so term(20) = a+19d

You MUST know these to be able to work with sequences

Answer 4

where did you get the 10 from and how?