Question
A pendulum and a mass spring system are both undergoing simple harmonic motion on Earth (use g = 10 N/kg). It is observed that every time the pendulum goes back and forth, the spring has gone up and down 14 times. If the pendulum has a length of 5 meters and the mass is 100 g, determine:
The period of the pendulum?
sec
The period of the spring-mass system?
sec
the spring constant of the spring?
N/m
On the moon, how many times will the mass bounce up and down when the pendulum swings back and forth one time?
times
The period of the pendulum?
sec
The period of the spring-mass system?
sec
the spring constant of the spring?
N/m
On the moon, how many times will the mass bounce up and down when the pendulum swings back and forth one time?
times
Answers
T^2 = 4*pi^2*(L/g).
T^2 = 39.48*(5/10) = 19.74
T = 4.44 s. = Period of pendulum.
T = 4.44s/14 = 0.317 s.
T^2 = 39.48*(5/10) = 19.74
T = 4.44 s. = Period of pendulum.
T = 4.44s/14 = 0.317 s.
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