T^2 = 4*pi^2*(L/g).
T^2 = 39.48*(5/10) = 19.74
T = 4.44 s. = Period of pendulum.
T = 4.44s/14 = 0.317 s.
A pendulum and a mass spring system are both undergoing simple harmonic motion on Earth (use g = 10 N/kg). It is observed that every time the pendulum goes back and forth, the spring has gone up and down 14 times. If the pendulum has a length of 5 meters and the mass is 100 g, determine:
The period of the pendulum?
sec
The period of the spring-mass system?
sec
the spring constant of the spring?
N/m
On the moon, how many times will the mass bounce up and down when the pendulum swings back and forth one time?
times
1 answer
1 answer