Asked by Anamika
ANDY HAS TWICE AS MANY MARBLES AS PANDY AND SANDY HAS HALF AS MANY HAS ANDY AND PANDY PUT TOGETHER .ANDY HAS 110 MARBLES WHICH IS 115 MARBLES LESS THAN SANDY.HOW MANY MARBLES EACH OF THEM HAVE
Answers
Answered by
PsyDAG
First, please do not use all capitals. Online it is like SHOUTING. Not only is it rude, but it is harder to understand. Thank you.
A = 2P = 110
S = .5(P + 2P) = .5 (55 + 110) = 82.5
It doesn't make sense, since they can't have a half marble. Is there a typo?
With your data, Andy is a no-brainer, 110.
Sandy = 110 + 115 = 225
2P = 110 therefore Pandy has 55.
A = 2P = 110
S = .5(P + 2P) = .5 (55 + 110) = 82.5
It doesn't make sense, since they can't have a half marble. Is there a typo?
With your data, Andy is a no-brainer, 110.
Sandy = 110 + 115 = 225
2P = 110 therefore Pandy has 55.
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