Asked by Daniel
An airplane flies at airspeed (relative to the air) of 430 km/h . The pilot wishes to fly due North (relative to the ground) but there is a 43 km/h wind blowing Southwest (direction 225◦).
In what direction should the pilot head the plane (measured clockwise from North)?
Answer in units of degrees.
In what direction should the pilot head the plane (measured clockwise from North)?
Answer in units of degrees.
Answers
Answered by
Steve
43/√2 = 30.4, so the wind's vector is (-30.4,-30.4)
If the plane flies on heading θ,
(-30.4,-30.4)+(430cos(θ-45°),430sin(θ-45°)) = (0,y)
so, we have -30.4 + 430cos(θ-45) = 0
cos(θ-45) = 30.4/430 = 4.05
so, the plane flies N41°E
If the plane flies on heading θ,
(-30.4,-30.4)+(430cos(θ-45°),430sin(θ-45°)) = (0,y)
so, we have -30.4 + 430cos(θ-45) = 0
cos(θ-45) = 30.4/430 = 4.05
so, the plane flies N41°E
Answered by
Daniel
is 41 degrees east of north the exact degree number??? because a computer program wants the exact number and i cant round over or under 1%...