find the complete zeros of the polynomial function. Write f in factored form.

f(x)=3x^4-10x^3-12x^2+122x-39

**Use the complex zeros to write f in factored form.**

f(x)=

Please show work

User Icon for Steve Steve answered
11 years ago

f(x) = (x+3)(3x-1)(x^2-6x+13)

the quadratic has roots 3±2i, so
f(x) = (x+3)(3x-1)(x-3-2i)(x-3+2i)

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the complete zeros of the given polynomial function, we will use the Rational Root Theorem and synthetic division to test different possible roots until we find a zero. Once we find a zero, we can use synthetic division again to obtain a lower degree polynomial, which will make the factoring process easier.

The Rational Root Theorem states that if a polynomial function has a rational root p/q, where p is a factor of the constant term (in this case, 39) and q is a factor of the leading coefficient (in this case, 3), then p/q is a possible zero of the polynomial function.

Let's list all the possible rational zeros of the given polynomial f(x) = 3x^4 - 10x^3 - 12x^2 + 122x - 39:
- Factors of the constant term: ±1, ±3, ±13, ±39.
- Factors of the leading coefficient: ±1, ±3.

Using synthetic division, we test these possible rational zeros until we find a zero. We start with p/q = 1:

1 | 3 -10 -12 122 -39
| 3 -7 -19 103
+-------------------
3 -7 -19 103 64

The remainder is non-zero, so 1 is not a zero. Let's try p/q = -1:

-1 | 3 -10 -12 122 -39
| -3 13 -1 -121
+---------------------
3 -13 1 121 -160

Again, we have a non-zero remainder, so -1 is not a zero. Let's try p/q = 3:

3 | 3 -10 -12 122 -39
| 9 -3 -27 285
+-------------------
3 -1 -15 149 246

This time, we have a zero remainder, so 3 is a zero of the polynomial. Now, we can use synthetic division again with the quotient coefficients 3, -1, -15, and the divisor (x - 3) to obtain a lower degree polynomial:

(x - 3)(3x^3 - x^2 - 15x + 149) = 0

We need to find the zeros of the cubic polynomial 3x^3 - x^2 - 15x + 149 to complete the factored form. We can use a similar process to find the zeros:

3x^3 - x^2 - 15x + 149 = 0

No straightforward rational zeros are apparent, so we can use a graphing calculator or factoring techniques to find the remaining zeros, which are complex numbers.

Using a graphing calculator, we find that the zeros of the cubic polynomial are approximately x ≈ -1.79, x ≈ 3.39, and x ≈ 4.86.

Therefore, the complete zeros of the polynomial function f(x) = 3x^4 - 10x^3 - 12x^2 + 122x - 39 are x = 3, x ≈ -1.79, x ≈ 3.39, and x ≈ 4.86.

Hence, the factored form of the polynomial f(x) is:
f(x) = 3(x - 3)(x + 1.79)(x - 3.39)(x - 4.86)