Question

integrate by parts


çx (lnx)^2 dx

Answer 1

integrate by parts

x(lnx)^2

Answer 2

∫u dv = uv - ∫v du

So in ∫x(lnx)^2 dx

let u = (lnx)^2 and dv = x dx
du/dx = 2lnx (1/x) and v = (1/2)x^2
du = (2/x)(lnx) dx and v = (1/2)x^2

∫x(lnx)^2 dx = (1/2)(x^2)(lnx)^2 - ∫(1/2)x^2 (2/x)(lnx) dx
= (1/2)(x^2)(lnx)^2 - ∫(x)(lnx) dx

now let's do ∫(x)(lnx) dx

let u = lnx and dv = x dx
du/dx = 1/x and v = (1/2)x^2
du = (1/x) dx and v = (1/2)x^2

∫(x)(lnx) dx = (lnx)(1/2)(x^2) - ∫(1/2)(x^2)(1/x) dx
= (1/2)(x^2)(lnx) - ∫(1/2)x dx
= (1/2)(x^2)(lnx) - (1/4)x^2

So finally ...
∫x(lnx)^2 dx
= (1/2)(x^2)(lnx)^2 - ∫(x)(lnx) dx
= (1/2)(x^2)(lnx)^2 - ((1/2)(x^2)(lnx) - (1/4)x^2) )
= (1/2)(x^2)(lnx)^2 - (1/2)(x^2)(lnx) + (1/4)x^2)

better check my algebra, I should have written it out on paper first.