Asked by Yvette B.
                If Y varies inversely as X^2, determine what Y would be if X = 2 and another point on the equation is (1,8).
The answer I got was y=1/2^2=1/4
I'm not sure I worked this out correctly, is this correct?
            
        The answer I got was y=1/2^2=1/4
I'm not sure I worked this out correctly, is this correct?
Answers
                    Answered by
            bobpursley
            
    no.
y=k/x^2 then consider the point 1,8
8=k/1^2 k=8
y=8/x^2
if x is 2, then y=2
another way to think this out: y is 8 when x is one, so if you double x, then y must be changed by 1/4, or y=2
    
y=k/x^2 then consider the point 1,8
8=k/1^2 k=8
y=8/x^2
if x is 2, then y=2
another way to think this out: y is 8 when x is one, so if you double x, then y must be changed by 1/4, or y=2
                    Answered by
            Yvette B.
            
    Thank you!
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.