Asked by Anonymous
prove that
mean of cubes of first n natural numbers is [n(n+1)(n+1)]/4
mean of cubes of first n natural numbers is [n(n+1)(n+1)]/4
Answers
Answered by
Steve
by induction, you can show that
n
∑ k^3 = n^2 * (n+1)^2 / 4
k=1
now divide by n, and you're done.
n
∑ k^3 = n^2 * (n+1)^2 / 4
k=1
now divide by n, and you're done.
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