heat lost by metal + heat gained by H2O = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] +[mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute and solve for specific heat metal.
30 grams of a metal at 100 degrees Celsius is placed in a calorimeter containing 100 mL of water at 21 degrees Celsius. After a few minutes, the temperature inside the calorimeter is 24 degrees Celsius. What is the specific heat of the metal?
2 answers
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