Asked by LP

Find three consecutive odd integers such that the square of the first increased by product of the other two is 224.

Answers

Answered by Reiny
let the middle number be x
then the 1st is x-2
and the 3rd is x+2

(x-2)^2 + x(x+2) = 224
x^2 - 4x + 4 + x^2 + 2x = 224
2x^2 -2x - 220 = 0
x^2 - x - 110 = 0
(x-11)(x+10) = 0
x = 11 or x = -10, but x is to be odd
so
x = 11
and the three numbers are 9, 11, and 13

check:
9^2 + 11(13) = 224 , YEAH!
Answered by gricelis
i got this so correct omg im so happy

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