Asked by Anonymous
intergrate 3x-4/x^2-4x+4
Answers
Answered by
Damon
I assume you mean
(3x-4)dx/(x-2)^2
3x dx/(x-2)^2 - 4 dx/(x-2)^2
3[ -2/(x-2) + ln(x-2) ] -4 [ -1/(x-2) ]
-6/(x-2) + 3 ln(x-2) + 4/(x-2)
-2/(x-2) + 3 ln(x-2)
(3x-4)dx/(x-2)^2
3x dx/(x-2)^2 - 4 dx/(x-2)^2
3[ -2/(x-2) + ln(x-2) ] -4 [ -1/(x-2) ]
-6/(x-2) + 3 ln(x-2) + 4/(x-2)
-2/(x-2) + 3 ln(x-2)
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