The coefficients of static and kinetic friction between a 50 kg box and a horizontal surface are 0.64 and 0.17, respectively.

Question

(a) What is the acceleration of the object if a 335 N horizontal force is applied to the box?
m/s2

(b) What is the acceleration if the applied force is 465 N

Answer 1

(a) It takes a force of 0.64 M g = 314 N to make it move, so it will move in this case. The kinetic friction force opposing motion will be
0.17 M g = 83 N. The net applied force is
Fnet = 335 - 83 = 252 N
Acceleration = Fnet/M = 5.04 m/s^2

(b) The method of solution is the same.