Question

If you made up a solution of NaOH by adding 0.010 mole of solid NaOH to 1.0 liter of distilled water, what would be the pH of the solution?
pH = -log[H+]
pOH = -log[OH-]

and pH = pOH = 14

pOH = -log(0.01) = 2

2 + pH = 14; pH = 12
pH = the negative of the exponent of concentration

pH = the H+ concentration

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