Calculate the degree of polymerization n of polystyrene with a molecular weight of 3.091×106 g/mol.
2 answers
3.091 x 10^6** not 106
The monomeric unit is C6H5C*HC*H2
with the asterisks denoting the points at which the other monomers hook. Therefore, the monomeric empirical formula mass is 104 (that's not 10^4 but 104 as in one hundred four.
So 3.091E6/104 = ? = n.
I suppose that must be rounded to a whole number.
with the asterisks denoting the points at which the other monomers hook. Therefore, the monomeric empirical formula mass is 104 (that's not 10^4 but 104 as in one hundred four.
So 3.091E6/104 = ? = n.
I suppose that must be rounded to a whole number.