Asked by Anonymous
A spherical party balloon is being inflated with helium pumped in at a rate of 12 cubic feet per minute. How fast is the radius growing at the instant when the radius has reached 1 ft?
Answers
Answered by
Jennifer
V = 4/3*PI*r^3
dV/dt = 12 = 4*PI*r^2*dr/dt = 4*PI*1^2*dr/dt
Solve for dr/dt, the rate at which the radius is growing
dV/dt = 12 = 4*PI*r^2*dr/dt = 4*PI*1^2*dr/dt
Solve for dr/dt, the rate at which the radius is growing
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