Asked by Anonymous
Will, Micah and Sue went to dinner. Will paid 1/3 of the dinner bill. Micah and Sue paid in the ratio 2:5. If sue paid $6 more than Will, how much did the dinner cost?
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Answers
Answered by
bobpursley
w+m+s=dc
w=dc/3
s=w+6
m/2=s/5 or m=2s/5
dc/3 +2s/5+s=dc
but s=dc/3 +6
dc/3+2/5 (dc/3 +6)+dc/3 +6=dc
check all that, and solve for dc
w=dc/3
s=w+6
m/2=s/5 or m=2s/5
dc/3 +2s/5+s=dc
but s=dc/3 +6
dc/3+2/5 (dc/3 +6)+dc/3 +6=dc
check all that, and solve for dc
Answered by
Anonymous
Thank you so much!
Answered by
no
Will micah and sue went to dinner.will paid 1 / 3 of the dinner bill.micah and sue paid in the ratio of 2 : 5.if sue paid 6 $ more than will how much did the dinner cost.
Answered by
Sophia
305
Answered by
answer: correct
Its 42
Answered by
Sau win
$42
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