Question
A heat pump has a coefficient of performance of 4.5. If the heat pump absorbs 46.1 cal of heat from the cold outdoors in each cycle, what is the amount of heat expelled to the warm indoors?
(in cal)
tried everything but got nothing.
(in cal)
tried everything but got nothing.
Answers
CoP=4.5
CoP=Qh/(Qh-Qc)=1/{1-(Qc/Qh)}=4.5
Qc/Qh=0.78
Qc=46.1 cal
Qh= Qc/0.78 = 46.1/0.78=59.1 cal
CoP=Qh/(Qh-Qc)=1/{1-(Qc/Qh)}=4.5
Qc/Qh=0.78
Qc=46.1 cal
Qh= Qc/0.78 = 46.1/0.78=59.1 cal
thanks :)
Related Questions
A heat pump has a coefficient of performance of 4.5. If the heat pump absorbs 46.1 cal of heat from...
(a) What is the best coefficient of performance for a heat pump that has a hot reservoir temperature...
(a) What is the best coefficient of performance for a heat pump that has a hot reservoir temperature...