A protein has a molecular weight of 98,300 grams/ mole. What will be the osmotic pressure if 0.128 grams of this protein I dissolved in 15.0 ml of water at 20 degrees calcias?

Answer 1

Note the correct spelling of celsius.

pi = osmotic pressure in atm.
R is 0.08206 L*atm/mol*K
pi = MRT
M = mols/L. mols = grams/molar mass. Solve for mols, then M, then pi. Technically this won't be quite right since M = mols/L soln and the problem quotes adding the solute to 15.0 mL.