Asked by chelseavanderguard
can someone help me please or explain this better? i'm having trouble. thank you, chelsea
Three ropes hold a zeppelin in place, but two of the ropes break. The remaining rope holds the zeppelin with a tension of 255 N at an angle of 40 degrees with the ground due to a wind. The weight (vertical force) of the zeppelin and its contents is 200 N, and the upward buoyant force is 450 N. The wind creates a horizontal force of 45 N on the zeppelin. What is the resultant force on the zeppelin?
Three ropes hold a zeppelin in place, but two of the ropes break. The remaining rope holds the zeppelin with a tension of 255 N at an angle of 40 degrees with the ground due to a wind. The weight (vertical force) of the zeppelin and its contents is 200 N, and the upward buoyant force is 450 N. The wind creates a horizontal force of 45 N on the zeppelin. What is the resultant force on the zeppelin?
Answers
Answered by
chelseavanderguard
R=(45-200)+(450-200)=-210+250
R=Square Root of -210squared + 250squared = 136 N
Is this correct? Please help
R=Square Root of -210squared + 250squared = 136 N
Is this correct? Please help
Answered by
drwls
No, it is not correct. Where did the 45 - 200 come from? You cannot subtract newtons from degrees.
Since the zeppelin is still being held in the wind, there is no acceleration. The net force on the zeppelin is zero.
This is the resultant of buoyancy, weight, rope tension and wind forces.
Since the zeppelin is still being held in the wind, there is no acceleration. The net force on the zeppelin is zero.
This is the resultant of buoyancy, weight, rope tension and wind forces.
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