Asked by Cameron
The lethal inhalation dose of Sarin for a 200lb person has been determined to be 0.0015 mg. Determine the LD50 of Sarin that researchers used to calculate this lethal inhalation dose.
1.4 x 10-4 mg/kg
0.16 x 10-4 mg/kg
1.8 x 10-5 mg/kg
0.00023 mg/kg
1.4 x 10-4 mg/kg
0.16 x 10-4 mg/kg
1.8 x 10-5 mg/kg
0.00023 mg/kg
Answers
Answered by
DrBob222
I believe this can be done with the right factor. Convert 200 lb to kg; I think that is about 91 kg but you need to do it more accurately. Then
(?mg/kg) x 91 = 0.0015 mg.
Solve for ?mg. I have about 1.6E-5 mg/kg and that is one of the answers.
(?mg/kg) x 91 = 0.0015 mg.
Solve for ?mg. I have about 1.6E-5 mg/kg and that is one of the answers.
Answered by
Brady
0.16 x 10-4 mg/kg
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