Asked by Gamel
Suppose that an object is 100 lbs when it is at sea level. find the value of c that makes the equation true. (Sea level is 3963 miles from the center of the earth.) Use the value of c you found in the previous question to determin how much the object would weight in the Death valley (282 feet below sea level
Answers
Answered by
drwls
You need to show the equation you are referring to, that has a constant c in it, which you are supposed to make true.
I will assume the equation is, for the 100# object in question,
W = C/R^2
where R is the diatance of the object from the center of the Earth in miles and W is in lb.
C = W R^2 = 100*3963^2 = 1.5705*10^9 lb
*mile^2
At 282 ft below sea level, the distance from the center of the earth is reduced by 282/5280 = 0.0534 miles, so the new weight W' is
W' = C/R^2
= 1.5705*10^9 lb /(3963-.0534)^2
= 100.064 lb
I will assume the equation is, for the 100# object in question,
W = C/R^2
where R is the diatance of the object from the center of the Earth in miles and W is in lb.
C = W R^2 = 100*3963^2 = 1.5705*10^9 lb
*mile^2
At 282 ft below sea level, the distance from the center of the earth is reduced by 282/5280 = 0.0534 miles, so the new weight W' is
W' = C/R^2
= 1.5705*10^9 lb /(3963-.0534)^2
= 100.064 lb
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