Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
You are conducting experiments with your x-ray diffractometer. (a) A specimen of molybdenum is exposed to a beam of monochromat...Asked by vanesa
You are conducting experiments with your x-ray diffractometer.
(a) A specimen of molybdenum is exposed to a beam of monochromatic x-rays of wavelength set by the Kα line of silver. Calculate the value of the smallest Bragg angle, θhkl, at which you can expect to observe reflections from the molybdenum specimen.
DATA:
λKα of Mo = 0.721 Å
lattice constant of Mo, a = 3.15 Å
λKα of Ag = 0.561 Å
lattice constant of Ag, a = 4.09 Å
unanswered
(b) If you wish to repeat the experiment described in part (a) but using an electron diffractometer, across what vale of potential difference must electrons be accelerated from rest in order to give the identical value for the smallest Bragg angle, θhkl?
unanswered
(a) A specimen of molybdenum is exposed to a beam of monochromatic x-rays of wavelength set by the Kα line of silver. Calculate the value of the smallest Bragg angle, θhkl, at which you can expect to observe reflections from the molybdenum specimen.
DATA:
λKα of Mo = 0.721 Å
lattice constant of Mo, a = 3.15 Å
λKα of Ag = 0.561 Å
lattice constant of Ag, a = 4.09 Å
unanswered
(b) If you wish to repeat the experiment described in part (a) but using an electron diffractometer, across what vale of potential difference must electrons be accelerated from rest in order to give the identical value for the smallest Bragg angle, θhkl?
unanswered
Answers
Answered by
Antonio
hi, I'm one of the community TA for 3.091x. Please stop cheating, it's quite silly.
Answered by
Odesa
a) 7.23
b) 475 ev
b) 475 ev
Answered by
MIT2
Odesa, why are you helping people to cheat?
Answered by
Odesa
how do I believe you?
Answered by
Anonymous
please odesa tell me because they are not suppose to be here if they know it all
Answered by
XXX
Odesa, like to help each other to cheat because he/she like to be cheated... Hahaha
There are no AI answers yet. The ability to request AI answers is coming soon!