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You wish to increase the carbon content of a slab of steel by exposing it to a carburizing atmosphere at elevated temperature....Asked by kiril
You wish to increase the carbon content of a slab of steel by exposing it to a carburizing atmosphere at elevated temperature. The carbon concentration in the steel before carburization is 165.0 ppm and is initially uniform through the thickness of the steel. The atmosphere of the carburizing furnace maintains a carbon concentration of 7715.0 ppm at the surface of the steel. Calculate the time required to carburize steel so that the concentration of carbon at a depth of 61.5 x 10-2 cm is one half the value of the carbon concentration at the surface. The diffusion coefficient of carbon in steel is 3.091 x 10-7 cm2/s at the carburizing temperature. Express your answer in hours.
DATA: Error Function Values
erf(ξ < 0.6), use the approximation erf ξ = ξ
erf(1.0) = 0.84
erf(2.0) = 0.998
DATA: Error Function Values
erf(ξ < 0.6), use the approximation erf ξ = ξ
erf(1.0) = 0.84
erf(2.0) = 0.998
Answers
Answered by
BRA
777.78
Answered by
mango
could you please write how you've got your numbers? I'm trying to calculate it on my own and the result is not different
Answered by
Paul
I am having trouble to and BRA state this on Odesa question
Use:
concentration of carbon at a depth
___________________________________
4*(3.091*10^-7)*0,26277
Use:
concentration of carbon at a depth
___________________________________
4*(3.091*10^-7)*0,26277
Answered by
mango
it doesnt work for me, in my question i have 38.0 x 10-2 and when i put it into the pattern above- the calculations are wrong. Could you please explain it in a simple way? why there is 4 and 0.26277 there?
Answered by
MIT
DO NOT ANSWER THIS QUESTION, IT IS FOR A MIDTERM ON AN ONLINE CLASS
Answered by
Steve
We know that. You're not MIT. Now kindly go away and stop spamming this site with your nonsense.
Answered by
MIT2
What do you gain by cheating? A little chart that says 100% but means nothing? What is the point?
Unless you are about 4 years old, you should know better. And you are spoiling it for everyone.
Unless you are about 4 years old, you should know better. And you are spoiling it for everyone.
Answered by
Ling
Step 1:
(0.5*7715.0 - 7715.0)/ (165.0 - 7715.0)= erf(ξ)
Step 2:
erf(ξ < 0.6), use the approximation erf ξ = ξ
Step 3:
t= d^2/4*D*ξ^2
d=61.5 x 10-2 cm
D=3.091 x 10-7 cm2/s
Step 4:
t in sec -> hours
Conversion seconds to hours is total/(60x60)
(0.5*7715.0 - 7715.0)/ (165.0 - 7715.0)= erf(ξ)
Step 2:
erf(ξ < 0.6), use the approximation erf ξ = ξ
Step 3:
t= d^2/4*D*ξ^2
d=61.5 x 10-2 cm
D=3.091 x 10-7 cm2/s
Step 4:
t in sec -> hours
Conversion seconds to hours is total/(60x60)
Answered by
Nerd
I Can't get the correct answer with the above method. !!!
Answered by
qpt
ξ= (0.5 * carbon concentration at the surface of the steel - carbon concentration at the surface of the steel)/ (carbon concentration in the steel before carburization - carbon concentration at the surface of the steel)
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