Asked by Shelby

I don't understand how to get the answer to this "Radical equations" deal.

The problem I'm having trouble with is

(Square Root) x-5 = 2 (square root) 6
Answered by Reiny
square both sides, then
(√(x-5))^2 = (2√6)^2
x-5 = 4(6)
x = 29

check:
Left Side = √(29-5
= √24
=√4 * √6
= 2√6 = Right Side
Answered by mamie
3index 4x-15+3=square6x
Answered by mamie
3(6x+7)= 3(x-5)