Asked by Samuel
A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle's diagonal measurement is 46 inches, find the height.
Answers
Answered by
MathGuru
Use the Pythagorean theorem:
a^2 + b^2 = c^2
x = height
x + 7 = width
Therefore:
x^2 + (x + 7)^2 = 46^2
Expand and try to factor. If this does not factor easily, use the quadratic formula to solve.
a^2 + b^2 = c^2
x = height
x + 7 = width
Therefore:
x^2 + (x + 7)^2 = 46^2
Expand and try to factor. If this does not factor easily, use the quadratic formula to solve.
Answered by
charys
A rectangle is drawn so the width is 3 inches longer than the height. If the rectangle's diagonal measurement is 55 inches, find the height.
There are no AI answers yet. The ability to request AI answers is coming soon!