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Suppose a revolving door at the bamk is spinning around once every 5 seconds. As you walk through, you push on the door for 2 s...Asked by Anonymous
Suppose a revolving door at the bamk is spinning around once every 5 seconds. As you walk through, you push on the door for 2 seconds, which increases the rotational speed so that it rotates once a second. What was the rotational acceleration due to your push?
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Answered by
Damon
T = 5 so f = 1/5 and 2 pi f = (2/5)pi rad/s
new T = 1 so f = 1 and 2 pi f = 2 pi rad/s
change in angular velocity =2 pi(4/5)
change in angular velocity per second = angular acceleration = 2 pi (4/5)/2
= 4 pi/5 rad/s^2
new T = 1 so f = 1 and 2 pi f = 2 pi rad/s
change in angular velocity =2 pi(4/5)
change in angular velocity per second = angular acceleration = 2 pi (4/5)/2
= 4 pi/5 rad/s^2
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