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The flywheel of an engine has a moment of inertia of 24 kg*m^2. a) if the radius of the wheel is 0.6m, what force is required t...Asked by Natasha
The flywheel of an engine has a moment of inertia of 24 kg*m^2.
a) if the radius of the wheel is 0.6m, what force is required to accelerate the wheel from rest to an angular velocity of 300 rpm in 6 seconds?
b) how many turns does it make during this time?
a) if the radius of the wheel is 0.6m, what force is required to accelerate the wheel from rest to an angular velocity of 300 rpm in 6 seconds?
b) how many turns does it make during this time?
Answers
Answered by
drwls
(a) compute the angular acceleration required in rad.s^2. Call it alpha
Torque = (moment of inertia)* (alpha)
= force * radius
Solve for force
(b) avg. rpm * (1 min/60s)* 6s
= 15 revolutions
Torque = (moment of inertia)* (alpha)
= force * radius
Solve for force
(b) avg. rpm * (1 min/60s)* 6s
= 15 revolutions
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