Asked by Bruce
There are two polarizing filters that are out of alignment by 30 degrees. If the light of intensity 1.00 W/m^2 and initially polarized half-way between the two filters passes through the two filters, what is the intensity of the transmitted light?
I know the answer is 0.700 W/m^2, but I have no clue how to find that answer.
Thank you for any help!
I know the answer is 0.700 W/m^2, but I have no clue how to find that answer.
Thank you for any help!
Answers
Answered by
drwls
The fraction that gets through the first fiter is (cos15)^2 = 0.9330
The fraction of that which gets through the second filter is (cos30)^2 = 0.7500
Now take the product.
Actually, sheet polarizing "Polaroid" films lose even more than that, due to absorption.
The fraction of that which gets through the second filter is (cos30)^2 = 0.7500
Now take the product.
Actually, sheet polarizing "Polaroid" films lose even more than that, due to absorption.
Answered by
Bruce
The intensity of the light isn't halved after it passes through each filter? That's what I don't understand.
Thank you for your help!
Thank you for your help!
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