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Nitrogen & hydrogen goes react to form ammonia gas as follows: N2(g)+3H2(g)-->2NH3(g) At a certain temperature & pressure, 1.2L...Asked by Ezra
Nitrogen and hydrogen gases react to form ammonis gas as follows:
N2(g)+3H2(g)-->2NH3(g)
At a certain temperature and pressure, 1.2L of N2 reacts with 3.6L of H2. If all the N2 and H2 are consumed, what volume of NH3 at the same temperature and pressure will be produced?
I'd really appreciate an explanation as to how to go about doing this problem. It looks like it should be simple, but I can't seem to get a firm grasp on it.
N2(g)+3H2(g)-->2NH3(g)
At a certain temperature and pressure, 1.2L of N2 reacts with 3.6L of H2. If all the N2 and H2 are consumed, what volume of NH3 at the same temperature and pressure will be produced?
I'd really appreciate an explanation as to how to go about doing this problem. It looks like it should be simple, but I can't seem to get a firm grasp on it.
Answers
Answered by
bobpursley
on the left, 4 volumes=2volumes on right.
What is 2.4L?
What is 2.4L?
Answered by
Ezra
Could you provide more explanation as to where those numbers came from?
Answered by
Neil
First since there
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