assume that adults have IQ scores that are normally distributed with a mean of 105 and a standard deviation of 15 find the probability that a randomly selected adult has an IQ between 89 and 121 ?

2 answers

Convert to z-score using
(X-μ)/σ
where X=89 or 121, σ=15, μ=105.
Look up normal distribution table to find probability enclosed between these two z-scores.
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