Asked by shine

A neutron star has a mass of 1.27 × 1030 kg (about the mass of our sun) and a radius of 6.47 × 103 m. Suppose an object falls from rest near the surface of such a star. How fast would it be moving after it had fallen a distance of 0.0086 m? (Assume that the gravitational force is constant over the distance of the fall, and that the star is not rotating.)
Answered by Damon
assume you mean Mstar = 1.27*10^30
and r = 6.47 * 10^3

(1/2) m v^2 = Fg * .0086

Fg = G Mstar * m / r^2

so
v^2 = (2 G Mstar/r^2).0086
Answered by Anonymous
A neutron star has a mass of 2.1 1030 kg (about the mass of our sun) and a radius of 6.2 103 m (about the height of a good-sized mountain). Suppose an object falls from rest near the surface of such a star. How fast would this object be moving after it had fallen a distance of 0.013 m? (Assume that the gravitational force is constant over the distance of the fall and that the star is not rotating.)
Answered by jkhgh
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