Asked by Anonymous
Find the exact value of the intergal with limits 1 and 0 respectively for the x^2 e^2x dx.
Answers
Answered by
Steve
use integration by parts twice to get
∫x^2 e^2x dx = 1/4 e^2x (2x^2 - 2x + 1)
so, 1/4 (e^2 - 1)
∫x^2 e^2x dx = 1/4 e^2x (2x^2 - 2x + 1)
so, 1/4 (e^2 - 1)
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