Asked by Odesa

The fictitious compound, pandemonium carbonate Pn(CO3)2 hase a Ksp=3.091x10^-9M3 in water at room temperature. Calculate the solubility of Pn(CO3)2 in an aqueous solution of 1.11 M pandemonium sulfate Pn(SO4)2 (aq) . Express your answer in units of molarity.
Answered by chocheche
please, i need the answer too!
Answered by qwerty
2.63e-5
Answered by bhanu
0.917e-3
Answered by Paul
I had 2.63e-5 as the right answer
Answered by Odesa
qwerty and paul are right. Thank you both.
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