Write five 7-digit numbers that are even. The sum of the digits in each number is 29.

Answer 1

all you have to do is come up with 1 such number, then shuffle the digits around, leaving the last (even) digit alone.

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now shuffle the digits, leaving 8 where it is. There are 6! = 720 ways to do it.

It was easy to come up with, since 29-8=21, so I just picked 3 pairs of digits that add up to 7, and stuck 'em in front of the 8.

Answer 2

Thank you for your response. But, I just don't understand what you wrote. It seems completely different than what the question is asking. Because the statement says all 7 numbers are even?

Answer 3

Thank you Eric!! I understand after thinking about your solution. You are 100% correct!!! :=)

Answer 4

good job. Thanks for puzzling it out on your own.