Asked by John

write the formulas for the following compounds
Sodium chlorate i put NaCl
Lead (II) phosphate i put Pb2P
For Magnesium hydrogen carbonate i had no clue!
then it stats state the number of electrons lost or gained in forming each of these Ions. I didn't understand the question but they were
Mg2+
Ca2+
Br- and Ag+
then it says name each ions in the question and tell whether they are anions or cataions
for Mg2+ i put cation
for Ca2+ i put cation
for Br- i put anion
and for Ag+ i put cation

thanks in advance
Answered by gamacmua
most of them are true... except for question with polyatomic ion

Sodium chlorate = NaClO3 (chlorate is a polyatomic ion)
Lead(II) phosphate = Pb3(PO4)2
Magnesium hydrogencarbonate =Mg(HCO3)2
*** you need to review your polyatomic ion)
Answered by ~christina~
sodium chlorate: NaClO3
lead II phosphate: Pb3(PO4)2

Magnesium => Mg
Hydrogen carbonate=> HCO3

since in group 2 (Mg)

then Mg(HCO3)2
Answered by John
ok but what about the rest of the questions?
Answered by ~christina~

then it stats state the number of electrons lost or gained in forming each of these Ions. I didn't understand the question but they were
Mg2+ <b> so since it's 2+ then it has lost 2 electrons</b>
Ca2+ <b> 2 as well</b>
Br-<b>gained 1 e-</b> and Ag+ </b> since it's + then it obviously lost 1 e-</b>
then it says name each ions in the question and tell whether they are anions or cataions
for Mg2+ i put cation
for Ca2+ i put cation
for Br- i put anion
and for Ag+ i put cation
<b> all these are okay</b>
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