Asked by Elizabeth
A motorist makes a journey of 240 km from Singapore to Malacca to visit his inlaws at an average speed of x kilometers.
On his return journey, his average speed is reduced by 6km/hour due to traffic.
If the return journey takes 20 minutes longer, form an equation with x and solve it to find the average speed of each journey, giving your answer correct to two decimal places.
So: 240/x is the number of hours taken for the first journey.
240/x-6 is the time it takes for the return journey.
What do I do next? Please help!
On his return journey, his average speed is reduced by 6km/hour due to traffic.
If the return journey takes 20 minutes longer, form an equation with x and solve it to find the average speed of each journey, giving your answer correct to two decimal places.
So: 240/x is the number of hours taken for the first journey.
240/x-6 is the time it takes for the return journey.
What do I do next? Please help!
Answers
Answered by
Steve
and you know that the return journey takes 1/3 hour longer than the one going.
240/x + 1/3 = 240/(x-6)
x = 3(1+±481) = 68.80
check:
240/62.80 = 3.82
240/68.80 = 3.49 = 3.82
difference: .33 hr = 20 min
you got the setup right, but didn't take that final step. Be sure to analyze <b>everything</b> they tell you, and the solution will emerge.
240/x + 1/3 = 240/(x-6)
x = 3(1+±481) = 68.80
check:
240/62.80 = 3.82
240/68.80 = 3.49 = 3.82
difference: .33 hr = 20 min
you got the setup right, but didn't take that final step. Be sure to analyze <b>everything</b> they tell you, and the solution will emerge.
Answered by
Steve
oops. typo that's
3(1±√481)
3(1±√481)
Answered by
Elizabeth
thanks!
Answered by
ammar
dhek bhai phely minutes ko convert kro phir jo answer aye us ko 240se add kr k equation se agey solve krlo
Answered by
titu mir
galat galat ammar galat
Answered by
Anonymous
kk thanks
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