Asked by Anonymous

An atomic nucleus of radon initially moving at 515 m/s emits an alpha particle in the direction of its velocity, and the new nucleus slows to 417 m/s. If the alpha particle has a mass of 4u, and the original nucleus of radon had a mass of 222u, what speed does the alpha particle have when it is emitted?

Answers

Answered by Anonymous
Use conservation of momentum

222*515 = 417*(222-4) + 4*valpha

where valpha is the speed of the alpha particle
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