Question
An object of mass .550kg is lifted from the floor to a height of 3.5m at a constant speed. If the object is released from rest after it is lifted, what is its kinetic energy just before it hits the floor? What is its velocity? Show your work and units.
Answers
Ke = (1/2) m v^2 = m g h = .55*9.81*3.5 joules
v = sqrt (2 g h) - sqrt (9.81*3.5) m/s
v = sqrt (2 g h) - sqrt (9.81*3.5) m/s
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