Asked by Marie

Magnetite, an iron ore with formula Fe3O4, can be reduced by treatment with hydrogen to yield iron metal and water vapor.
(a) Write the balanced equation. (Use the lowest possible coefficients.)
1Fe3O4(s) + 4H2(g)-> 3Fe(s) + 4H2O(g)

(b) This process requires 36 kcal for every 1.00 mol of Fe3O4 reduced. How much energy (in kilocalories) is required to produce 63 g of iron?
. kcal

(c) How many grams of hydrogen are needed to produce 69 g of iron?
. g

Answers

Answered by DrBob222
36 kcal for 3 mols Fe or 12 kcal for 1 mol Fe = 55.85 g Fe.
12 kcal x (63/55.85) = ? kcal
Answered by Anonymous
Magnetite, an iron ore with formula Fe3O4, can be reduced by treatment with hydrogen to yield iron metal and water vapor.
(a) Write the balanced equation. (Use the lowest possible coefficients.)
1Fe3O4(s) + 4H2(g)-> 3Fe(s) + 4H2O(g)

How many grams of hydrogen are needed to produce 81g of iron?
Answered by Jurnee
b)

Find the molecular weight of Fe3 which is 167.535
Then divide the 63g of iron by the molecular weight (167.535) and you get 0.376.
Then you multiply 0.376 by the 36 kcal to get your answer of 13.536 or rounded to 14.
Answered by anil
whatis formula iron ore dencity
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