Question
How many moles of glucose , C6H12O6, can be "burned" biologically when 10.0 mol of oxygen is available.
C6H12O6(s) + 602(g)---6CO2(g) + 6H2O(l)
C6H12O6(s) + 602(g)---6CO2(g) + 6H2O(l)
Answers
Kat
1.67 mol
Anonymous
Solving for glucose. 10.0 mol divided by 6 O2 is the answer (1.67)