Question
integrate
-sinx/ã4+cos^2x dx
-sinx/ã4+cos^2x dx
Answers
Jess 1
integrate
-sinx/square root 4+cos^2x dx
Steve
I assume you mean
sin x/√(4+cos^2 x)
let u = cos x
du = -sin x dx
and you have
-∫1/√(4+u^2) du
standard hyperbolic trig substitution is used to get
-arcsinh(u/2)
= -arcsinh(cosx / 2)
sin x/√(4+cos^2 x)
let u = cos x
du = -sin x dx
and you have
-∫1/√(4+u^2) du
standard hyperbolic trig substitution is used to get
-arcsinh(u/2)
= -arcsinh(cosx / 2)