integrate
-sinx/�square root 4+cos^2x dx
integrate
-sinx/�ã4+cos^2x dx
2 answers
I assume you mean
sin x/√(4+cos^2 x)
let u = cos x
du = -sin x dx
and you have
-∫1/√(4+u^2) du
standard hyperbolic trig substitution is used to get
-arcsinh(u/2)
= -arcsinh(cosx / 2)
sin x/√(4+cos^2 x)
let u = cos x
du = -sin x dx
and you have
-∫1/√(4+u^2) du
standard hyperbolic trig substitution is used to get
-arcsinh(u/2)
= -arcsinh(cosx / 2)