Question
a person is standing at the top of a 58 m tall hill. He stumbles and falls. As he rolls down the hill, magically friction has no effect on him! when he is still 25.0 m above the base of the hill determine how fast he is moving.
Answers
Henry
V^2 = Vo^2 + 2g*d.
V^2 = 0 + 19.8*(58-25) = 646.8
V = 25.4 m/s.
V^2 = 0 + 19.8*(58-25) = 646.8
V = 25.4 m/s.