Asked by Anonymous
What concentration of the lead ion, Pb^{2+} , must be exceeded to precipitate PbCl2 from a solution that is 1.00 x 10^{-2} M in the chloride ion, Cl^- ? Ksp for lead chloride is 1.17×10−5 .
Answers
Answered by
DrBob222
Ksp = (Pb^2+)(Cl^-)^2
Substitute for Ksp and (Cl^-) and solve for (Pb^2+)
Substitute for Ksp and (Cl^-) and solve for (Pb^2+)
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